60x-1,2x^2=0

Solution for 60x-1,2x^2=0 equation:

60x-1.2x^2=0

a = -1.2; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·(-1.2)·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*-1.2}=\frac{-120}{-2.4}
=+50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*-1.2}=\frac{0}{-2.4}
=0
$